在Python中如何使用沒有0x的十六進制()?

[英]How to use hex() without 0x in Python?

本文翻译自 mahmood 查看原文 2013-05-07 71009 python

The hex() function in python, puts the leading characters 0x in front of the number. Is there anyway to tell it NOT to put them? So 0xfa230 will be fa230.

python中的十六進制()函數，將字符0x放在數字前面。有什么可以告訴它不要放它們嗎?0xfa230就是fa230。

The code is

代碼是

import fileinput
f = open('hexa', 'w')
for line in fileinput.input(['pattern0.txt']):
   f.write(hex(int(line)))
   f.write('\n')

4 个解决方案

#1

101

>>> format(3735928559, 'x')
'deadbeef'

#2

Use this code:

使用這段代碼:

'{:x}'.format(int(line))

it allows you to specify a number of digits too:

它還允許您指定一些數字:

'{:06x}'.format(123)
# '00007b'

For Python 2.6 use

對於Python 2.6使用

'{0:x}'.format(int(line))

或

'{0:06x}'.format(int(line))

#3

You can simply write

你可以簡單地寫

hex(x)[2:]

to get the first two characters removed.

刪除前兩個字符。

#4

Old style string formatting:

老樣式字符串格式:

In [3]: "%02x" % 127
Out[3]: '7f'

New style

新風格

In [7]: '{:x}'.format(127)
Out[7]: '7f'

Using capital letters as format characters yields uppercase hexadecimal

使用大寫字母作為格式字符產生大寫的十六進制

In [8]: '{:X}'.format(127)
Out[8]: '7F'

Docs are here.

文檔都在這里。

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