Class and std::async on class member in C++
I'm try to write a class member which calls another class member multiple times in parallel.
我試着寫一個類成員，它並行多次調用另一個類成員。
I wrote a simple example of the problem and can't even get to compile this. What am I doing wrong with calling std::async? I guess the problem would be with how I'm passing the the function.
我寫了一個簡單的問題示例，甚至無法編譯。調用std :: async我做錯了什么？我想問題就在於我如何傳遞函數。
#include <vector>
#include <future>
using namespace std;
class A
{
int a,b;
public:
A(int i=1, int j=2){ a=i; b=j;}
std::pair<int,int> do_rand_stf(int x,int y)
{
std::pair<int,int> ret(x+a,y+b);
return ret;
}
void run()
{
std::vector<std::future<std::pair<int,int>>> ran;
for(int i=0;i<2;i++)
{
for(int j=0;j<2;j++)
{
auto hand=async(launch::async,do_rand_stf,i,j);
ran.push_back(hand);
}
}
for(int i=0;i<ran.size();i++)
{
pair<int,int> ttt=ran[i].get();
cout << ttt.first << ttt.second << endl;
}
}
};
int main()
{
A a;
a.run();
}
compilation:
匯編：
g++ -std=c++11 -pthread main.cpp
2 个解决方案
#1
39
do_rand_stf is a non-static member function and thus cannot be called without a class instance (the implicit this parameter.) Luckily, std::async handles its parameters like std::bind, and bind in turn can use std::mem_fn to turn a member function pointer into a functor that takes an explicit this parameter, so all you need to do is to pass this to the std::async invocation and use valid member function pointer syntax when passing the do_rand_stf:
do_rand_stf是一個非靜態成員函數，因此在沒有類實例（隱式this參數）的情況下無法調用。幸運的是，std :: async處理其參數如std :: bind，而bind又可以使用std :: mem_fn來將一個成員函數指針轉換為一個帶有顯式this參數的仿函數，所以你需要做的就是將它傳遞給std :: async調用，並在傳遞do_rand_stf時使用有效的成員函數指針語法：
auto hand=async(launch::async,&A::do_rand_stf,this,i,j);
There are other problems in the code, though. First off, you use std::cout and std::endl without #includeing <iostream>. More seriously, std::future is not copyable, only movable, so you cannot push_back the named object hand without using std::move. Alternatively, just pass the async result to push_back directly:
但是，代碼中還有其他問題。首先，在沒有#includeing
ran.push_back(async(launch::async,&A::do_rand_stf,this,i,j));
#2
2
You can pass the this pointer to a new thread:
您可以將this指針傳遞給新線程：
async([this]()
{
Function(this);
});
注意！
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