the string looks like this
字符串看起來像這樣
"blabla blabla-5 amount-10 blabla direction-left"
How can I get the number just after "amount-"
, and the text just after "direction-"
?
如何在“amount-”之后獲取數字,以及在“direction-”之后的文本?
17
This uses regular expressions and the exec method:
這使用正則表達式和exec方法:
var s = "blabla blabla-5 amount-10 blabla direction-left";
var amount = parseInt(/amount-(\d+)/.exec(s)[1], 10);
var direction = /direction-([^\s]+)/.exec(s)[1];
The code will cause an error if the amount or direction is missing; if this is possible, check if the result of exec is non-null before indexing into the array that should be returned.
如果缺少數量或方向,代碼將導致錯誤;如果可能,請在索引到應返回的數組之前檢查exec的結果是否為非null。
38
This will get all the numbers separated by coma:
這將使所有數字被昏迷分開:
var str = "10 is smaller than 11 but greater then 9"; var pattern = /[0-9]+/g; var matches = str.match(pattern);
After execution, the string matches
will have values "10,11,9"
執行后,字符串匹配的值為“10,11,9”
If You are just looking for thew first occurrence, the pattern will be /[0-9]+/
- which will return 10
如果你只是第一次出現,那么模式將是/ [0-9] + / - 這將返回10
(There is no need for JQuery)
(不需要JQuery)
6
You can use regexp as explained by w3schools. Hint:
您可以使用w3schools解釋的正則表達式。暗示:
str = "blabla blabla-5 amount-10 blabla direction-left"
alert(str.match(/amount-([0-9]+)/));
Otherwize you can simply want all numbers so use the pattern [0-9]+ only. str.match would return an array.
另外,你可以簡單地想要所有數字,所以只使用模式[0-9] +。 str.match將返回一個數組。
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