I am trying to iterate through my xml document's nodes to get the value for <username>Ed</username>
in each node. I am using Linq to sort the XDocument first, then attempting to loop through the nodes. I can't seem to find the correct foreach loop to achieve this. Any help is appreciated.
我嘗試遍歷xml文檔的節點,以獲取每個節點中
var doc = XDocument.Load("files\\config.xml");
var newDoc = new XDocument(new XElement("Config",
from p in doc.Element("Config").Elements("Profile")
orderby int.Parse(p.Element("order").Value)
select p));
foreach (XElement xe in newDoc.Nodes())
{
MessageBox.Show(xe.Element("username").Value);
}
// XML document
<Config>
<Profile>
<id>Scope</id>
<username>Scope 1</username>
<password>...</password>
<cdkey>0000</cdkey>
<expkey></expkey>
<cdkeyowner>Scope</cdkeyowner>
<client>W2BN</client>
<server>[IP]</server>
<homechannel>Lobby</homechannel>
<load>1</load>
<order>2</order>
</Profile>
<Profile>
<id>Scope 2</id>
<username>Scope 2</username>
<password>...</password>
<cdkey>0000</cdkey>
<expkey></expkey>
<cdkeyowner>Scope</cdkeyowner>
<client>W2BN</client>
<server>[IP]</server>
<homechannel>Lobby</homechannel>
<load>1</load>
<order>1</order>
</Profile>
</Config>
40
Try this. Not sure why you need the second doc.
試試這個。不知道為什么需要第二個醫生。
foreach (XElement xe in doc.Descendants("Profile"))
{
MessageBox.Show(xe.Element("username").Value);
}
4
Its easier to use a XPathDocument and a XPath expression.
使用XPathDocument和XPath表達式更容易。
var doc = new XPathDocument("files\\config.xml")
foreach (var username in doc.CreateNavigator().Select("//username")
{
...
}
1
If you are looking for inner node, i.e. recursive like, you can check for the element has element. For example assum you reading your xml from database
如果您正在尋找內部節點,例如遞歸,您可以檢查元素是否有元素。例如,當您從數據庫中讀取xml時
string xmlRoot = "select XmlItem from db";
XDocument doc = XDocument.Parse(xmlRoot);
List<XElement> xElementList = doc.Descendants().Tolist();
foreach(XElement element in xElementList )
{
// read the element and do with your node
if(element.HasElements)
{
// here you can reach nested node
}
}
本站翻译的文章,版权归属于本站,未经许可禁止转摘,转摘请注明本文地址:https://www.itdaan.com/blog/2011/02/14/7210e4f8f223702d923fa71561f9f02e.html。