0  

If you're trying to do this in some fancy way, like adapting the grouper recipe in the itertools docs to take an iterable of group sizes instead of a fixed group size… take a step back and write the "dumb" version first.—just write a loop.

如果你試圖以某種奇特的方式做到這一點,比如在itertools文檔中調整石斑魚配方來采用可迭代的組大小而不是固定的組大小...退后一步並首先編寫“啞”版本.-只寫一個循環。

First, split the whole string, the same way you split each line in your line-by-line version.

首先,拆分整個字符串,就像在逐行版本中拆分每一行一樣。

One thing: mapping list over your values won't do any good; that'll just turn, e.g., '23' into ['2', '3'], and there's not much good you can do with that. You want a list of numbers, which you're then going to break up into a rows (each row also being a list of numbers—the same row you got by mapping int over line.split() in your line-by-line version).

一件事:映射列表超過您的值將不會有任何好處;這只會轉變,例如'23'進入['2','3'],你可以用它做很多好事。你想要一個數字列表,然后你將它們分成一行(每一行也是一個數字列表 - 你通過line.split()在你的逐行映射int得到的同一行版)。

So, here's some pseudocode:

所以,這里有一些偽代碼:

values = input("Enter the numbers: ").split()
nums = [int(value) for value in values]
size = 1
start = 0
while start < len(nums):
    rownums = nums[start:start+size]
    make sure len(rownums) == size
    check rownums the same way you checked each line
    update size and start
if you got here without seeing any errors, it's valid

0  

One way to do this is to generate each row of Pascal's triangle, and use islice to grab a list of the current row length from the user data and see if the data matches the row.

一種方法是生成Pascal三角形的每一行,並使用islice從用戶數據中獲取當前行長度的列表,並查看數據是否與行匹配。

from itertools import islice

def pascal():
    """ Pascal's triangle generator """
    a = [1]
    while True:
        yield a
        #Generate next row from current row
        a = [x + y for x, y in zip([0] + a, a + [0])]

def test_pascal(values):
    it = map(int, values.split())
    ok = True
    for row in pascal():
        data = list(islice(it, len(row)))
        if not data:
            break
        if data != row:
            ok = False
            print('bad data', data, row)
            break
    return ok

# Test

values = '1 1 1 1 2 1 1 3 3 1 1 4 6 4 1 1 5 10 10 5 1'
print(test_pascal(values))

values = '1 1 1 1 2 1 1 3 3 1 1 4 6 5 1'
print(test_pascal(values))

output

True
bad data [1, 4, 6, 5, 1] [1, 4, 6, 4, 1]
False