[英]Result of 'sizeof' on array of structs in C?

In C, I have an array of structs defined like:


struct D
    char *a;
    char *b;
    char *c;

static struct D a[] = {

I would like to determine the number of elements in the array, but sizeof(a) returns an incorrect result: 48, not 2. Am I doing something wrong, or is sizeof simply unreliable here? If it matters I'm compiling with GCC 4.4.

我想確定數組中元素的數量,但sizeof(a)返回的結果不正確:48,而不是2.我做錯了什么,或者這里的sizeof簡單不可靠?如果重要的話我正在使用GCC 4.4進行編譯。

3 个解决方案



sizeof a / sizeof a[0];

This is a compile-time constant, so you can use it to, for example, create another array:


#define N sizeof a / sizeof a[0]
int n_a[N];



sizeof gives you the size in bytes, not the number of elements. As Alok says, to get the number of elements, divide the size in bytes of the array by the size in bytes of one element. The correct C idiom is:


sizeof a / sizeof a[0]



sizeof returns the size in memory of the passed element. By dividing the size of an array by a single element size, you get the elements count.


Note that the element size may include some padding bytes as well. For this reason, a padded struct (e.g. when a char member is followed by a pointer) will have a sizeof value greater than it members size sum.


On the other hand, don't let it bother you when counting elements in an array: sizeof(a) / sizeof(a[0]) will still work as smooth as expected.

另一方面,在計算數組中的元素時不要讓它煩惱:sizeof(a)/ sizeof(a [0])仍然可以像預期的那樣平滑。



粤ICP备14056181号  © 2014-2020 ITdaan.com