HDU 1711:Number Sequence(KMP模板,求位置)


Number Sequence

Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 40388    Accepted Submission(s): 16659

Problem Description

Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make a[K] = b[1], a[K + 1] = b[2], ...... , a[K + M - 1] = b[M]. If there are more than one K exist, output the smallest one.

Input

The first line of input is a number T which indicate the number of cases. Each case contains three lines. The first line is two numbers N and M (1 <= M <= 10000, 1 <= N <= 1000000). The second line contains N integers which indicate a[1], a[2], ...... , a[N]. The third line contains M integers which indicate b[1], b[2], ...... , b[M]. All integers are in the range of [-1000000, 1000000].

Output

For each test case, you should output one line which only contain K described above. If no such K exists, output -1 instead.

Sample Input

2
13 5
1 2 1 2 3 1 2 3 1 3 2 1 2
1 2 3 1 3
13 5
1 2 1 2 3 1 2 3 1 3 2 1 2
1 2 3 2 1

Sample Output

6

-1

題意

給出兩個數組,問第二個數組是不是第一個數組的子序列,如果是,輸出第二個數組的第一個元素在第一個數組中的位置,否則輸出-1

AC代碼

#include <bits/stdc++.h>
#define ll long long
#define ms(a) memset(a,0,sizeof(a))
using namespace std;
const int maxn=1e6+10;
int a[maxn],b[maxn];
int Next[maxn];
int  n,m;
// Next數組下標從1開始
void getNext()
{
	int j,k;
	j=0;k=-1;Next[0]=-1;
	while(j<m)
	{
		if(k==-1||b[j]==b[k])
			Next[++j]=++k;
		else
			k=Next[k];
	}
}
/*
返回第二個數組在第一個數組中首次出現的位置
返回的位置是從0開始的。
*/
int KMP_Index()
{
	int i=0,j=0;
	getNext();
	while(i<n&&j<m)
	{
		if(j==-1||a[i]==b[j])
		{
			i++;j++;
		}
		else
			j=Next[j];
	}
	if(j==m)
		return i-m;
	else
		return -1;
}
int main(int argc, char const *argv[])
{
	int t;
	scanf("%d",&t);
	while(t--)
	{
		scanf("%d%d",&n,&m);
		ms(a);
		ms(b);
		ms(Next);
		for(int i=0;i<n;i++)
			scanf("%d",&a[i]);
		for(int i=0;i<m;i++)
			scanf("%d",&b[i]);
		if(KMP_Index()!=-1)
			printf("%d\n",KMP_Index()+1);
		else
			printf("%d\n",KMP_Index());
	}
	return 0;
}

 


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