[Swift]LeetCode566. 重塑矩陣 | Reshape the Matrix
In MATLAB, there is a very useful function called 'reshape', which can reshape a matrix into a new one with different size but keep its original data.
You're given a matrix represented by a two-dimensional array, and two positive integers r and c representing the row number and column number of the wanted reshaped matrix, respectively.
The reshaped matrix need to be filled with all the elements of the original matrix in the same row-traversing order as they were.
If the 'reshape' operation with given parameters is possible and legal, output the new reshaped matrix; Otherwise, output the original matrix.
Example 1:
Input: nums = [[1,2], [3,4]] r = 1, c = 4 Output: [[1,2,3,4]] Explanation:
The row-traversing of nums is [1,2,3,4]. The new reshaped matrix is a 1 * 4 matrix, fill it row by row by using the previous list.
Example 2:
Input: nums = [[1,2], [3,4]] r = 2, c = 4 Output: [[1,2], [3,4]] Explanation:
There is no way to reshape a 2 * 2 matrix to a 2 * 4 matrix. So output the original matrix.
Note:
- The height and width of the given matrix is in range [1, 100].
- The given r and c are all positive.
在MATLAB中，有一個非常有用的函數 reshape，它可以將一個矩陣重塑為另一個大小不同的新矩陣，但保留其原始數據。
給出一個由二維數組表示的矩陣，以及兩個正整數r和c，分別表示想要的重構的矩陣的行數和列數。
重構后的矩陣需要將原始矩陣的所有元素以相同的行遍歷順序填充。
如果具有給定參數的reshape操作是可行且合理的，則輸出新的重塑矩陣；否則，輸出原始矩陣。
示例 1:
輸入: nums = [[1,2], [3,4]] r = 1, c = 4 輸出: [[1,2,3,4]] 解釋: 行遍歷nums的結果是 [1,2,3,4]。新的矩陣是 1 * 4 矩陣, 用之前的元素值一行一行填充新矩陣。
示例 2:
輸入: nums = [[1,2], [3,4]] r = 2, c = 4 輸出: [[1,2], [3,4]] 解釋: 沒有辦法將 2 * 2 矩陣轉化為 2 * 4 矩陣。 所以輸出原矩陣。
注意：
- 給定矩陣的寬和高范圍在 [1, 100]。
- 給定的 r 和 c 都是正數。
172ms
1 class Solution { 2 func matrixReshape(_ nums: [[Int]], _ r: Int, _ c: Int) -> [[Int]] { 3 //創建一個二維數組 4 var res:[[Int]] = [[Int]](repeating: [Int](repeating: 0, count: c), count: r) 5 let len:Int = nums.count 6 if len == 0 || r * c != len * nums[0].count 7 { 8 return nums 9 } 10 var count:Int = 0 11 for i in 0..<len 12 { 13 for j in 0..<nums[0].count 14 { 15 res[count / c][count % c] = nums[i][j] 16 count++ 17 } 18 } 19 return res 20 } 21 } 22 23 /*擴展Int類，實現自增++、自減--運算符*/ 24 extension Int{ 25 //++前綴:先自增再執行表達示 26 static prefix func ++(num:inout Int) -> Int { 27 //輸入輸出參數num 28 num += 1 29 //返回加1后的數值 30 return num 31 } 32 //后綴++:先執行表達式后再自增 33 static postfix func ++(num:inout Int) -> Int { 34 //輸入輸出參數num 35 let temp = num 36 //num加1 37 num += 1 38 //返回加1前的數值 39 return temp 40 } 41 //--前綴:先自減再執行表達示 42 static prefix func --(num:inout Int) -> Int { 43 //輸入輸出參數num 44 num -= 1 45 //返回減1后的數值 46 return num 47 } 48 //后綴--:先執行表達式后再自減 49 static postfix func --(num:inout Int) -> Int { 50 //輸入輸出參數num 51 let temp = num 52 //num減1 53 num -= 1 54 //返回減1前的數值 55 return temp 56 } 57 }
36ms
1 class Solution { 2 func matrixReshape(_ nums: [[Int]], _ r: Int, _ c: Int) -> [[Int]] { 3 if c * r != nums.count * nums[0].count{ 4 return nums 5 } 6 var res = Array(repeating: Array(repeating: 0,count: c) ,count: r) 7 var count = 0 8 for i in 0..<nums.count{ 9 for j in 0..<nums[0].count{ 10 res[count / c][count % c] = nums[i][j] 11 count += 1 12 } 13 } 14 15 return res 16 } 17 }
36ms
1 class Solution { 2 func matrixReshape(_ nums: [[Int]], _ r: Int, _ c: Int) -> [[Int]] { 3 guard !nums.isEmpty else { 4 return [[]] 5 } 6 7 guard nums.count * nums[0].count == r*c else { 8 return nums 9 } 10 11 var result = [[Int]](repeating: [Int](repeating: 0, count: c), count: r) 12 var index = 0 13 let arr = nums.flatMap {$0} 14 for row in 0..<r { 15 for col in 0..<c { 16 result[row][col] = arr[index] 17 index += 1 18 } 19 } 20 21 return result 22 } 23 }
40ms
1 class Solution { 2 func matrixReshape(_ nums: [[Int]], _ r: Int, _ c: Int) -> [[Int]] { 3 let row = nums.count 4 let column = nums[0].count 5 6 if (row == r && column == c) || row * column != r * c { 7 return nums 8 } 9 10 var result = [[Int]]() 11 var index = 0 12 for _ in 0..<r { 13 var newRow = [Int]() 14 for _ in 0..<c { 15 newRow.append(nums[index / column][index % column]) 16 index += 1 17 } 18 result.append(newRow) 19 } 20 return result 21 } 22 }
40ms
1 class Solution { 2 func matrixReshape(_ nums: [[Int]], _ r: Int, _ c: Int) -> [[Int]] { 3 let rows = nums.count 4 let cols = nums[0].count 5 if r*c != rows*cols { 6 return nums 7 } 8 var numbers = [Int]() 9 for row in nums { 10 for item in row { 11 numbers.append(item) 12 } 13 } 14 var reshaped = [[Int]]() 15 var rIndex = 0 16 var cIndex = 0 17 var row = [Int]() 18 numbers.forEach{ item in 19 if cIndex == c { 20 cIndex = 0 21 rIndex += 1 22 reshaped.append(row) 23 row.removeAll() 24 } 25 row.append(item) 26 cIndex += 1 27 } 28 reshaped.append(row) 29 return reshaped 30 } 31 }
44ms
1 class Solution { 2 func matrixReshape(_ nums: [[Int]], _ r: Int, _ c: Int) -> [[Int]] { 3 4 guard nums.count * nums[0].count == r * c else { 5 return nums 6 } 7 8 var res = [[Int]]() 9 var tmp = [Int]() 10 var tmpCount = 0 11 12 for num in nums { 13 for n in num { 14 tmp.append(n) 15 if tmp.count >= c { 16 res.append(tmp) 17 tmp.removeAll() 18 } 19 } 20 } 21 22 return res 23 } 24 }
44ms
1 class Solution { 2 func matrixReshape(_ nums: [[Int]], _ r: Int, _ c: Int) -> [[Int]] { 3 let numbers = Array(nums.joined()) 4 if numbers.count != r*c { 5 return nums 6 } 7 8 var reshaped = Array(repeating:[Int](), count:r) 9 for count in 0..<numbers.count { 10 reshaped[count/c].append(numbers[count]) 11 } 12 return reshaped 13 } 14 }
48ms
1 class Solution { 2 func matrixReshape(_ nums: [[Int]], _ r: Int, _ c: Int) -> [[Int]] { 3 let count = nums.count * nums[0].count; 4 if count != r * c { 5 return nums; 6 } 7 var result = Array<[Int]>() 8 var temp = Array<Int>() 9 10 for array in nums { 11 for num in array { 12 temp.append(num) 13 if temp.count >= c { 14 result.append(temp); 15 temp.removeAll() 16 } 17 } 18 } 19 return result; 20 } 21 }
48ms
1 class Solution { 2 func matrixReshape(_ nums: [[Int]], _ r: Int, _ c: Int) -> [[Int]] { 3 var reshapedMatrix = [[Int]]() 4 5 for _ in stride(from: 0, to: r, by: 1) { 6 var tempRow = [Int]() 7 for _ in stride(from: 0, to: c, by: 1) { 8 tempRow.append(0) 9 } 10 reshapedMatrix.append(tempRow) 11 } 12 13 let matrixSize = nums.count * nums[0].count 14 let reshapedMatrixSize = r * c 15 if matrixSize != reshapedMatrixSize { 16 return nums 17 } 18 for i in stride(from: 0, to: reshapedMatrixSize, by: 1) { 19 reshapedMatrix[i/c][i%c] = nums[i/nums[0].count][i%nums[0].count] 20 } 21 return reshapedMatrix 22 } 23 }
52ms
1 class Solution { 2 func matrixReshape(_ nums: [[Int]], _ r: Int, _ c: Int) -> [[Int]] { 3 if nums.count * nums[0].count != r * c { 4 return nums 5 } 6 var temp = [Int](),result2 = [[Int]]() 7 for itemArray in nums { 8 temp += itemArray 9 } 10 for i in 0..<r { 11 result2.append([Int](temp[i*c..<i*c+c])) 12 } 13 return result2 14 } 15 }
76ms
1 class Solution { 2 func matrixReshape(_ nums: [[Int]], _ r: Int, _ c: Int) -> [[Int]] { 3 guard nums.count * nums.first!.count == r * c else { 4 return nums 5 } 6 7 var newA = [[Int]]() 8 var tmpA = [Int]() 9 for subA in nums { 10 tmpA += subA 11 } 12 13 for index in stride(from: 0, to: r * c, by: c) { 14 newA.append(Array(tmpA[index..<index+c])) 15 } 16 17 return newA 18 } 19 }
84ms
1 class Solution { 2 func matrixReshape(_ nums: [[Int]], _ r: Int, _ c: Int) -> [[Int]] { 3 var new: [Int] = [] 4 for temp: [Int] in nums { 5 for i: Int in temp { 6 new.append(i) 7 } 8 } 9 if r * c > new.count { 10 return nums 11 } 12 var sq: [[Int]] = [] 13 for j in 1...r { 14 var tempSq: [Int] = [] 15 for a in 0..<c { 16 tempSq.append(new[(j-1)*c+a]) 17 } 18 sq.append(tempSq) 19 } 20 return sq 21 } 22 }
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