2016年08月17 -
I=[[1,2,3,4],[5,6,7,8]]
print([i for i in zip(I)]) 结果[([1, 2, 3, 4],), ([5, 6, 7, 8],)]
可见zip(I)就是在内部加了() data=[i for i in zip(*I)]
结果[(1, 5), (2
2009年07月08 - I have the following code for adding to/extracting from Zip. I'm trying to refactor this to make it test-ready. Can someone provide pointers on how I
2011年05月13 - I know there is another thread on this subject but I still face this problem even after using all solutions. Is there any other way to generate zip fi