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hdu 1159 Common Subsequencedp乞讨LCS 繁体
2015年07月18 - Common Subsequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 24489 Accepted

HDU 1159 Common Subsequence (线性dpLCS) 繁体
2015年02月13 - Common SubsequenceTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 25383 Accepted Submission

hdoj 1159 Common SubsequenceLCS】【DP 繁体
2017年06月02 - Common Subsequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 28494 Accepted Su

hdu 1159 Common SubsequenceLCS 基础入门】 繁体
2013年08月05 - 链接: http://acm.hdu.edu.cn/showproblem.php?pid=1159 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=28195#problem/A

HDU 1159 Common Subsequence(裸LCS 繁体
2018年07月21 - 传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1159 Common Subsequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/

HDU - 1159 Common Subsequence (简单LCS 繁体
2014年07月17 - HDU - 1159 Common Subsequence 题意: 在两个字符串x,y中,求它们最长的公共子串长度 分析: 存在x[i] == y[j]时,则公共子串长度+1,否则,维护当前最大值 状态:dp[i][j]:表示以x[i], y[j]

HDU 1159 Common Subsequence(最长公共子序列(LCS) 动态规划(DP)) 繁体
2017年08月12 - 原题Common SubsequenceTime Limit:1000MS Memory Limit:10000KB 64bit IO Format:%I64d & %I64uDescriptionA subsequence of a given sequence is the given

hdu 题目1159 Common SubsequenceDP 繁体
2013年08月13 - Common Subsequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 17779 Accept

dp Problem B:Common SubsequenceHDU 1159 繁体
2018年03月25 - Problem B Time Limit : 2000/1000ms (Java/Other) Memory Limit :65536/32768K (Java/Other) Total Submission(s) : 1 Accepted Submission(s) : 1

HDU 1159 Common Subsequencedp+最长公共子序列】 繁体
2017年07月17 - Common Subsequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 39559 Accepted Submissi


 
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