php中的数组引用问题

本文翻译自 Ashish 查看原文 2011-11-15 80 reference/reference/ php/php/ arrays/arrays/ pass-by-referencepass-by-reference

I am trying to run following code:

我正在尝试运行以下代码：

$a = array('aa');

function my_func (& $m) {
    return $m;
}

$c = & my_func($a);
$c[] = 'bb';
var_dump($a);
echo '--------';
var_dump($c);

My expectation were that $a and $c would have same reference. But the result is different.

我的期望是$ a和$ c会有相同的参考。但结果却不同。

Result i got was:

我得到的结果是：

array(1) { [0]=> string(2) "aa" } --------array(2) { [0]=> string(2) "aa" [1]=> string(2) "bb" }

What is wrong in above piece of code?

上面的代码有什么问题？

1 个解决方案

I think what you are looking for is function returning by reference (this in conjunction with passing by reference in your example).

我认为你要找的是通过引用返回的函数（这与你的例子中的引用一起传递）。

Here is an example:

这是一个例子：

function &my_func(&$m) {
    return $m;
}

$a = array('aa');
$c = &my_func($a);
$c[] = 'bb';

var_dump($a);
echo "---\n";
var_dump($c);

Outputs:

输出：

array(2) {
  [0]=>
  string(2) "aa"
  [1]=>
  string(2) "bb"
}
---
array(2) {
  [0]=>
  string(2) "aa"
  [1]=>
  string(2) "bb"
}

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