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1 LeetCode122:Best Time to Buy and Sell Stock II
2014年05月26 - at the same time (ie, you must sell the stock before you buy again). 解题思路: 这题与上一题Best Time to Buy and Sell Stock相比,其实还更简单,扫描一遍数组,当前前元素大于前一个元素,则将其差值累加到max中,最后
2 #Leetcode# 122. Best Time to Buy and Sell Stock II
2018年11月19 - https://leetcode.com/problems/best-time-to-buy-and-sell-stock-ii/ Say you have an array for which the ith element is the price of a given stock
3 Leetcode题解 122. Best Time to Buy and Sell Stock II
2016年08月17 - 假设有一个数组,它的第i个元素是一个给定的股票在第i天的价格。设计一个算法来找到最大的利润。你可以完成尽可能多的交易(多次买卖股票)。然而,你不能同时参与多个交易(你必须在再次购买前出售股票)。 解题思路 在Best Time to Buy and Sell Stock系列中,和本题最像
4 leetcode 122. Best Time to Buy and Sell Stock II
2018年03月27 - transactions at the same time (ie, you must sell the stock before you buy again). 思路很简单,只要看到价格涨,就在最低点买进,最高点卖出! class Solution(object): def
5 [LeetCode122]Best Time to Buy and Sell Stock II
2016年01月26 - at the same time (ie, you must sell the stock before you buy again). 题意类似于股价,每天价格不一样,每天都可以出手或入手,求最终最大收益 思路:可以考虑动态规划,求出来前i-1天的最大收益,比较i天价格和i-1价格,如果大于则前i天
6 LeetCode122. Best Time to Buy and Sell Stock II
2017年10月22 - 这两周开始接触贪心算法,顾名思义就是使其利益最大化了。先选一道最简单的相关题目来练练手。 LeetCode122. Best Time to Buy and Sell Stock II Say you have an array for which the ith
7 leetCode 122 Best Time to Buy and Sell Stock II
2015年05月27 - leetCode 122 Best Time to Buy and Sell Stock II Say you have an array for which the ith element is the price of a given stock on day i. Design
8 [LeetCode]Best Time to Buy and Sell Stock II
2014年03月09 - in multiple transactions at the same time (ie, you must sell the stock before you buy again). Have you been asked
9 leetcodeBest Time to Buy and Sell Stock II
2015年04月05 - transactions at the same time (ie, you must sell the stock before you buy again). Accept: 6ms 思路: 同 Stock I,先求diff,然后将 diff[i] > 0的全部加起来即可
10 Leetcode:Best Time to Buy and Sell Stock II
2015年01月15 - at the same time (ie, you must sell the stock before you buy again). 分析:贪心算法。如果可以交易多次,那么只要当前一个价格比前一个价格高我们就可以交易,最终可以获得最大利益。代码如下: class Solution { public

 
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